In mathematics, particularly in calculus, a stationary point of a differentiable function of one variable is a point on the graph of the function where the function's derivative is zero. Informally, it is a point where the function "stops" increasing or decreasing (hence the name). For a differentiable function of several real variables, a stationary point is a point on the surface of the graph where all its partial derivatives are zero (equivalently, the gradient is zero). Stationary points are easy to visualize on the graph of a function of one variable: they correspond to the points on the graph where the tangent is horizontal (i.e., parallel to the x-axis). For a function of two variables, they correspond to the points on the graph where the tangent plane is parallel to the xy plane. (Wikipedia).
From playlist l. Differential Calculus
Exploring Stationary Points (2 of 3: Introductory Examples regarding nature of Stationary Points)
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From playlist Applications of Differentiation
Using the Second Derivative (2 of 5: Turning Point vs Stationary Point analogy)
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Stationary Points: Step-by-Step Guide
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From playlist Applications of Differentiation
KS5 - Stationary & Turning Points
"Maxima and minima and stationary points."
From playlist Differentiation (AS/Beginner)
Sign of the Derivative (6 of 7: Locating stationary points)
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From playlist Applications of Differentiation
Graphing Stationary Points (3 of 3: Visualising the second derivative)
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From playlist Applications of Differentiation
From playlist Applications of Differentiation
Nature of Stationary Points From Second Derivative | Differentiation | A Level Maths
HOW TO DETERMINE TGE NATURE OF STATIONARY POINTS USING DIFFERENTIATION AND SECOND DERIVATIVES To classify stationary points into maximum, minimum or point of inflection, find the value of the second derivative at the stationary point. If negative, the point is s maximum. If positive, th
From playlist AS Level Maths Pure - AQA, Edexcel and OCR MEI
A-Level Maths: G3-11 [Gradients: The Second Derivative Test Part 1]
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Stationary Points - Coordinates, Nature and Curve Sketching | Differentiation | A Level Maths
Here we look at finding the coordinates of the stationary points of a curve, determining their nature using the second derivative and a gradient table, and then sketching the curve, labelling the stationary points. If the second derivative at a stationary point is negative, the point is a
From playlist AS Level Maths Pure - AQA, Edexcel and OCR MEI
Year 12/AS Pure Chapter 12.6 (Differentiation)
Here, we take a look at how we can ascertain the nature of stationary points (maxima, minima, points of inflection) using two methods. The first method is by inspecting the gradient either side of the stationary point, and the second method we examine is by using the second-order derivativ
From playlist Year 12/AS Edexcel (8MA0) Mathematics: FULL COURSE
How to Escape Saddle Points Efficiently by Praneeth Netrapalli
DISCUSSION MEETING : STATISTICAL PHYSICS OF MACHINE LEARNING ORGANIZERS : Chandan Dasgupta, Abhishek Dhar and Satya Majumdar DATE : 06 January 2020 to 10 January 2020 VENUE : Madhava Lecture Hall, ICTS Bangalore Machine learning techniques, especially “deep learning” using multilayer n
From playlist Statistical Physics of Machine Learning 2020
Understanding Stationary Points (1 of 3: Classifications)
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Powered by https://www.numerise.com/ C2 Differentiation (2)
From playlist Core 2 Differentiation
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🔥Python Data Science Training: https://www.edureka.co/data-science-python-certification-course This Edureka Video on Time Series Analysis n Python will give you all the information you need to do Time Series Analysis and Forecasting in Python. Machine Learning Tutorial Playlist: https://g
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Graphing Derivatives (3 of 4: Process to graphically find the primitive)
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From playlist Applications of Differentiation
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From playlist Applications of Differentiation
Stationary Points On A Curve | Differentiation | A Level Maths
FINDING COORDINATES OF STATIONARY POINTS ON A CURVE USING DIFFERENTIATION Stationary points are points on a curve where the gradient is zero. They can be a maximum, a minimum or a point of inflection. Differentiate the function, set equal to zero and solve for X values. Finally substitut
From playlist AS Level Maths Pure - AQA, Edexcel and OCR MEI